જો frac{2 sin alpha}{1+cos alpha+sin alpha}=x | vedclass

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(B) આપેલ છે કે $\frac{2 \sin \alpha}{1+\cos \alpha+\sin \alpha}=x$. અંશ અને છેદને $(1-(\cos \alpha+\sin \alpha))$ વડે ગુણતા: $\frac{2 \sin \alpha(1-\c

Vedclass · Accepted Answer

$-x$

Vedclass · Answer

(B) આપેલ છે કે $\frac{2 \sin \alpha}{1+\cos \alpha+\sin \alpha}=x$. અંશ અને છેદને $(1-(\cos \alpha+\sin \alpha))$ વડે ગુણતા: $\frac{2 \sin \alpha(1-\cos \alpha-\sin \alpha)}{(1+\cos \alpha+\sin \alpha)(1-(\cos \alpha+\sin \alpha))}=x$ $\Rightarrow \frac{2 \sin \alpha(1-\cos \alpha-\sin \alpha)}{1^2-(\cos \alpha+\sin \alpha)^2}=x$ $\Rightarrow \frac{2 \sin \alpha(1-\cos \alpha-\sin \alpha)}{1-(\cos^2 \alpha+\sin^2 \alpha+2 \cos \alpha \sin \alpha)}=x$ $\sin^2 \alpha+\cos^2 \alpha=1$ નો ઉપયોગ કરતા: $\Rightarrow \frac{2 \sin \alpha(1-\cos \alpha-\sin \alpha)}{1-(1+2 \cos \alpha \sin \alpha)}=x$ $\Rightarrow \frac{2 \sin \alpha(1-\cos \alpha-\sin \alpha)}{-2 \cos \alpha \sin \alpha}=x$ $\Rightarrow \frac{1-\cos \alpha-\sin \alpha}{-\cos \alpha}=x$ $\Rightarrow \frac{1-\cos \alpha-\sin \alpha}{\cos \alpha}=-x$

જો $\frac{2 \sin \alpha}{1+\cos \alpha+\sin \alpha}=x$ હોય,તો $\frac{1-\cos \alpha-\sin \alpha}{\cos \alpha}=$

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