If $a$ and $b$ are roots of the equation $px^2 + qx + r = 0$,then $\lim_{x \rightarrow b} \frac{1 - \cos 2(px^2 + qx + r)}{2(px - pb)^2}$ is equal to

  • A
    $\frac{1}{2}(b - a)^2$
  • B
    $(a + b)^2$
  • C
    $\frac{1}{2}$
  • D
    $a^2 - 2ab + b^2$

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