यदि $\frac{x^3+3}{(x-3)^3}=a+\frac{b}{x-3}+\frac{c}{(x-3)^2}+\frac{d}{(x-3)^3}$ है, तो $(a+d)-(b+c)=$

  • A
    $49$
  • B
    $15$
  • C
    $-30$
  • D
    $-5$

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