If $M$ and $N$ are the mid-points of the sides $BC$ and $CD$ respectively of a parallelogram $ABCD$, then $AM + AN$ equals

  • A
    $\frac{4}{3} AC$
  • B
    $\frac{5}{3} AC$
  • C
    $\frac{3}{2} AC$
  • D
    $\frac{6}{5} AC$

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