If $a=2 \hat{i}+\hat{j}-3 \hat{k}$, $b=\hat{i}-2 \hat{j}+3 \hat{k}$, $c=-\hat{i}+\hat{j}-4 \hat{k}$ and $d=\hat{i}+\hat{j}+2 \hat{k}$, then $(a \times b) \times(c \times d)=$

  • A
    $-7 \hat{i}+\hat{j}+3 \hat{k}$
  • B
    $8 \hat{i}-36 \hat{j}+60 \hat{k}$
  • C
    $5 \hat{i}+\hat{j}-\hat{k}$
  • D
    $-8 \hat{i}-36 \hat{j}+12 \hat{k}$

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