If $u(x)$ and $v(x)$ are two independent solutions of the differential equation $\frac{d^{2} y}{d x^{2}}+b \frac{d y}{d x}+c y=0$, then which of the following is also a solution of the given differential equation?

  • A
    $y=5 u(x)+8 v(x)$
  • B
    $y=c_{1}\{u(x)-v(x)\}+c_{2} v(x)$, where $c_{1}$ and $c_{2}$ are arbitrary constants
  • C
    $y=c_{1}u(x) v(x)+c_{2} u(x) / v(x)$, where $c_{1}$ and $c_{2}$ are arbitrary constants
  • D
    $y=u(x) v(x)$

Explore More

Similar Questions

The general solution of the differential equation $(x+2y^3) \frac{dy}{dx} - y = 0, y > 0$ is

The general solution of the differential equation $\frac{d y}{d x}=\frac{2 y^2+1}{2 y^3-4 x y+y}$ is

If for $x \geq 0$,$y=y(x)$ is the solution of the differential equation $(x+1) dy = ((x+1)^{2} + y - 3) dx$ with $y(2) = 0$,then $y(3)$ is equal to:

If $\cos x \frac{dy}{dx} - y \sin x = 6x$ for $0 < x < \frac{\pi}{2}$ and $y(\frac{\pi}{3}) = 0$,then $y(\frac{\pi}{6})$ is equal to:

If $y(x)$ satisfies the differential equation $y^{\prime}-y \tan x=2 x \sec x$ and $y(0)=0$, then which of the following is true?
$(A)$ $y(\frac{\pi}{4}) = \frac{\pi^2}{8\sqrt{2}}$
$(B)$ $y(\frac{\pi}{3}) = \frac{\pi^2}{9}$
$(C)$ $y'(\frac{\pi}{4}) = \frac{\pi^2}{8\sqrt{2}} + \frac{\pi}{\sqrt{2}}$
$(D)$ $y'(\frac{\pi}{3}) = \frac{4\pi}{3} + \frac{2\pi^2\sqrt{3}}{9}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo