If x + y = frac{pi}{4}, then (1 + tan x)(1 + | vedclass

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(B) Given $x + y = \frac{\pi}{4}$.Taking $	an$ on both sides: $	an(x + y) = 	an(\frac{\pi}{4})$.Using the formula $	an(x + y) = \frac{	an x + 	a

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$2$

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(B) Given $x + y = \frac{\pi}{4}$.Taking $	an$ on both sides: $	an(x + y) = 	an(\frac{\pi}{4})$.Using the formula $	an(x + y) = \frac{	an x + 	an y}{1 - 	an x 	an y} = 1$.Therefore, $	an x + 	an y = 1 - 	an x 	an y$.Rearranging gives $	an x + 	an y + 	an x 	an y = 1$.Adding $1$ to both sides: $1 + 	an x + 	an y + 	an x 	an y = 1 + 1$.Factoring the left side: $(1 + 	an x) + 	an y(1 + 	an x) = 2$.$(1 + 	an x)(1 + 	an y) = 2$.

If $x + y = \frac{\pi}{4}$, then $(1 + \tan x)(1 + \tan y) =$

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