If $a, b$ and $c$ are non-coplanar unit vectors such that the angle between any two of them is $60^\circ$, and the vector $d = xa + yb + zc$ is perpendicular to both $a$ and $b$, then the value of $\frac{(x + y)}{z}$ is

  • A
    $-\frac{1}{2}$
  • B
    $-\frac{2}{3}$
  • C
    $-1$
  • D
    $0$

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