If y = a{e^x} + b{e^{-x}} + c where a, b, c a | vedclass

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(B) Given the equation $y = a{e^x} + b{e^{-x}} + c$. First derivative: $y' = \frac{d}{dx}(a{e^x} + b{e^{-x}} + c) = a{e^x} - b{e^{-x}}$. Second deriva

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$y'$

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(B) Given the equation $y = a{e^x} + b{e^{-x}} + c$. First derivative: $y' = \frac{d}{dx}(a{e^x} + b{e^{-x}} + c) = a{e^x} - b{e^{-x}}$. Second derivative: $y'' = \frac{d}{dx}(a{e^x} - b{e^{-x}}) = a{e^x} + b{e^{-x}}$. Third derivative: $y''' = \frac{d}{dx}(a{e^x} + b{e^{-x}}) = a{e^x} - b{e^{-x}}$. Comparing this with the first derivative,we see that $y''' = y'$.

If $y = a{e^x} + b{e^{-x}} + c$ where $a, b, c$ are parameters,then $y''' = $

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