If $X$ follows a binomial distribution with parameters $n = 6$ and $p$. If $9P(X = 4) = P(X = 2)$,then $p = $

  • A
    $\frac{1}{3}$
  • B
    $\frac{1}{2}$
  • C
    $\frac{1}{4}$
  • D
    $1$

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