If n(A) = m,then the total number of reflexiv | vedclass

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(B) The total number of elements in the Cartesian product $A 	imes A$ is $n(A 	imes A) = m 	imes m = m^2$.For a relation $R$ on $A$ to be reflexive

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$2^{m^2 - m}$

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(B) The total number of elements in the Cartesian product $A 	imes A$ is $n(A 	imes A) = m 	imes m = m^2$.For a relation $R$ on $A$ to be reflexive,it must contain all elements of the form $(a, a)$ for every $a \in A$.Since there are $m$ such elements,these $m$ elements must be present in $R$.The remaining elements in $A 	imes A$ are $m^2 - m$.Each of these remaining $m^2 - m$ elements can either be in $R$ or not in $R$.Therefore,the total number of ways to choose the remaining elements is $2^{m^2 - m}$.

If $n(A) = m$,then the total number of reflexive relations that can be defined on $A$ is-

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