If a function $f(x) = \begin{cases} \frac{\sqrt[3]{1+ax^2+bx^3}-\sqrt[3]{1-ax^2-bx^3}}{x^2}, & x < 0 \\ 5, & x=0 \\ \frac{\tan 3x - \sin 3x}{bx^3}, & x > 0 \end{cases}$ is continuous at $x=0$,then the geometric mean of $a$ and $b$ is

  • A
    $\frac{3}{2}$
  • B
    $\frac{9}{2}$
  • C
    $\frac{81}{4}$
  • D
    $\frac{9}{4}$

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