If a proton and an anti-proton come close to each other and annihilate, how much energy will be released?

The energy equivalent to a substance of mass $1 \,g$ is

Obtain the binding energy of the nuclei $^{56}_{26} Fe$ and $^{209}_{83} Bi$ in units of $MeV$ from the following data:
$m(^{56}_{26} Fe) = 55.934939 \; u$
$m(^{209}_{83} Bi) = 208.980388 \; u$ (in $; MeV$)

Calculate the binding energy of a nitrogen nucleus $\left[{ }_7^{14} N\right]$,given that the mass of the nucleus $m\left[{ }_7^{14} N\right] = 14.00307 \ u$. (Take mass of proton $m_p = 1.00783 \ u$ and mass of neutron $m_n = 1.00867 \ u$) (in $MeV$)

$1 \text{ amu}$ is equal to

Obtain the binding energy (in $MeV$) of a nitrogen nucleus $\left(^{14}_{7} N \right)$ given $m\left(^{14}_{7} N \right)=14.00307 \; u$. (Given: $m_{H} = 1.007825 \; u$,$m_{n} = 1.008665 \; u$) (in $; MeV$)