If a ray of light in a denser medium strikes | vedclass

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(C) According to the law of reflection,the angle of incidence $i$ is equal to the angle of reflection $r$,so $i = r$.According to Snell's Law,for ligh

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$\sin ^{-1}(	an r)$

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(C) According to the law of reflection,the angle of incidence $i$ is equal to the angle of reflection $r$,so $i = r$.According to Snell's Law,for light traveling from a denser medium to a rarer medium with refractive index $n$ (where $n$ is the refractive index of the denser medium relative to the rarer medium,$n > 1$):$\frac{\sin i}{\sin r^{\prime}} = \frac{1}{n}$Since $i = r$,we have $\frac{\sin r}{\sin r^{\prime}} = \frac{1}{n}$.Given that the reflected and refracted rays are at right angles to each other,the sum of the angles on the straight line is $r + 90^{\circ} + r^{\prime} = 180^{\circ}$.Therefore,$r^{\prime} = 90^{\circ} - r$.Substituting this into Snell's Law:$\frac{\sin r}{\sin(90^{\circ} - r)} = \frac{1}{n}$$\frac{\sin r}{\cos r} = \frac{1}{n}$$	an r = \frac{1}{n}$The critical angle $i_c$ is defined by $\sin i_c = \frac{1}{n}$.Comparing the two equations,we get $\sin i_c = 	an r$.Therefore,$i_c = \sin^{-1}(	an r)$.

If a ray of light in a denser medium strikes a rarer medium at an angle of incidence $i$,the angles of reflection and refraction are $r$ and $r^{\prime}$ respectively. If the reflected and refracted rays are at right angles to each other,the critical angle for the given pair of media is

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