If all the words (with or without meaning) ha | vedclass

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Question

(B) The letters in the word $SMALL$ are $A, L, L, M, S$. Total letters = $5$.Arranging these letters in alphabetical order: $A, L, L, M, S$.$1$. Words

Vedclass · Accepted Answer

$58$

Vedclass · Answer

(B) The letters in the word $SMALL$ are $A, L, L, M, S$. Total letters = $5$.Arranging these letters in alphabetical order: $A, L, L, M, S$.$1$. Words starting with $A$: The remaining letters are $L, L, M, S$. The number of arrangements is $\frac{4!}{2!} = \frac{24}{2} = 12$.$2$. Words starting with $L$: The remaining letters are $A, L, M, S$. The number of arrangements is $4! = 24$.$3$. Words starting with $M$: The remaining letters are $A, L, L, S$. The number of arrangements is $\frac{4!}{2!} = \frac{24}{2} = 12$.$4$. Words starting with $SA$: The remaining letters are $L, L, M$. The number of arrangements is $\frac{3!}{2!} = 3$.$5$. Words starting with $SL$: The remaining letters are $A, L, M$. The number of arrangements is $3! = 6$.$6$. Words starting with $SMA$: The remaining letters are $L, L$. The number of arrangements is $\frac{2!}{2!} = 1$.$7$. Words starting with $SMAL$: The remaining letter is $L$. The number of arrangements is $1! = 1$.$8$. The next word is $SMALL$.Total position = $12 + 24 + 12 + 3 + 6 + 1 + 1 + 1 = 60$.Wait,let's re-verify: $A... = 12$$L... = 24$$M... = 12$$SA... = 3$$SL... = 6$$SMA... = 1$ ($SMALL$ is the first word starting with $SMA$)Total = $12 + 24 + 12 + 3 + 6 + 1 = 58$.Therefore,the position of the word $SMALL$ is $58^{th}$.

If all the words (with or without meaning) having five letters,formed using the letters of the word $SMALL$ and arranged as in a dictionary,then the position of the word $SMALL$ is:

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