If the freezing point of an aqueous solution of salt $MX_4$ $(\alpha = 90\%)$ is $-3\ ^oC$,then its boiling point will be ........ $^oC$. (Assume it is $100\%$ ionized at the boiling temperature and $k_f = 1.86\ K\ kg\ mol^{-1}$,$k_b = 0.52\ K\ kg\ mol^{-1}$)

  • A
    $100.9$
  • B
    $101.3$
  • C
    $102.3$
  • D
    $103.3$

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Similar Questions

The only incorrect statement regarding Henry's law for a gas dissolving in water is

The elevation in the boiling point of an aqueous urea solution is $0.104 \ K$. What is its $\Delta T_{f}$ (in $K$) value? (Given for water: $K_{b} = 0.52 \ K \ kg \ mol^{-1}$,$K_{f} = 1.86 \ K \ kg \ mol^{-1}$)

Match the following.
List-$I$ List-$II$
$(A)$ Azeotrope $(I)$ $\Delta T_b = i K_b m$
$(B)$ Henry's law $(II)$ $p = K_H x$
$(C)$ Cryoscopic constant $(III)$ $\Delta T_f / m$
$(D)$ Van't Hoff factor $(IV)$ Deviation from Raoult's law
$(V)$ $\pi = CRT$

The correct answer is

$2.5 \ g$ of a non-volatile,non-electrolyte is dissolved in $100 \ g$ of water at $25^{\circ} C$. The solution showed a boiling point elevation by $2^{\circ} C$. Assuming the solute concentration is negligible with respect to the solvent concentration,the vapour pressure of the resulting aqueous solution is . . . . . . $mm$ of $Hg$ (nearest integer).
[Given : Molal boiling point elevation constant of water $(K_b) = 0.52 \ K \ kg \ mol^{-1}$,
$1 \ atm$ pressure $= 760 \ mm$ of $Hg$,molar mass of water $= 18 \ g \ mol^{-1}]$

Which of the following mixtures represents Proof Spirit (by volume)?

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