If one of the roots of 2x^{2} + 5x + 3 = 0 is | vedclass

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(D) For a quadratic equation $ax^{2} + bx + c = 0$,the product of the roots is given by $\alpha \cdot \beta = c/a$.Given the equation $2x^{2} + 5x + 3

Vedclass · Accepted Answer

$-3/2$

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(D) For a quadratic equation $ax^{2} + bx + c = 0$,the product of the roots is given by $\alpha \cdot \beta = c/a$.Given the equation $2x^{2} + 5x + 3 = 0$,we have $a = 2$,$b = 5$,and $c = 3$.Let the roots be $\alpha = -1$ and $\beta$ be the other root.Using the product of roots formula: $(-1) \cdot \beta = 3/2$.Therefore,$\beta = -3/2$.Alternatively,using the sum of roots: $\alpha + \beta = -b/a$.$-1 + \beta = -5/2$.$\beta = -5/2 + 1 = -3/2$.

If one of the roots of $2x^{2} + 5x + 3 = 0$ is $-1$,the other root is .............

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