If the following quadratic equation has two equal and real roots,then find the value of $k$: $(k+1)x^2 - 2(k-1)x + 1 = 0$.
- A$0$ and $3$
- B$1$ and $2$
- C$7$ and $-3$
- D$3$ and $-4$
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Similar Questions
Find whether the following equation has real roots. If real roots exist,find them.
$-2x^{2} + 3x + 2 = 0$
$-2x^{2} + 3x + 2 = 0$
Medium
View SolutionWhich of the following groups correctly matches the data of Part $I$ with the data of Part $II$?
Part $I$ Part $II$ $1.$ The discriminant of $x^{2}+5x+6=0$ $a. 1$ $2.$ The discriminant of $x^{2}+5x+4=0$ $b. 9$ $3.$ The discriminant of $x^{2}+4x+3=0$ $c. 4$ $4.$ The discriminant of $x^{2}+6x+5=0$ $d. 16$
| Part $I$ | Part $II$ |
| $1.$ The discriminant of $x^{2}+5x+6=0$ | $a. 1$ |
| $2.$ The discriminant of $x^{2}+5x+4=0$ | $b. 9$ |
| $3.$ The discriminant of $x^{2}+4x+3=0$ | $c. 4$ |
| $4.$ The discriminant of $x^{2}+6x+5=0$ | $d. 16$ |
Difficult
View SolutionIf the following quadratic equation has two equal and real roots,then find the value of $k$: $x^{2} + 2kx + 4 = 0$.
Medium
View SolutionCheck whether the equation $6x^2 - 7x + 2 = 0$ has real roots, and if it has, find them by the method of completing the squares.
Medium
View SolutionValues of $k$ for which the quadratic equation $2x^{2}-kx+k=0$ has equal roots is
Medium
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