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(D) The given quadratic equation is $2x^{2}-kx+k=0$.Comparing this with the standard form $ax^{2}+bx+c=0$,we get $a=2$,$b=-k$,and $c=k$.For a quadrati

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$0, 8$

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(D) The given quadratic equation is $2x^{2}-kx+k=0$.Comparing this with the standard form $ax^{2}+bx+c=0$,we get $a=2$,$b=-k$,and $c=k$.For a quadratic equation to have equal roots,the discriminant $D$ must be equal to $0$.$D = b^{2}-4ac = 0$Substituting the values,we get $(-k)^{2}-4(2)(k) = 0$.$k^{2}-8k = 0$Factoring out $k$,we get $k(k-8) = 0$.Therefore,$k=0$ or $k=8$.Thus,the required values of $k$ are $0$ and $8$.

Values of $k$ for which the quadratic equation $2x^{2}-kx+k=0$ has equal roots is

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