If only $\frac{1}{51}$ of the main current is to be passed through a galvanometer,then the shunt required is $R_1$. If only $\frac{1}{11}$ of the main voltage is to be developed across the galvanometer,then the resistance required is $R_2$. Find the ratio $\frac{R_2}{R_1}$.

The circular coil of a galvanometer has $50$ turns. The coil has a radius of $1 \ cm$. The coil is placed in a radial magnetic field of $0.010 \ T$. The torsion coefficient of the spring on which the coil hangs is $3 \times 10^{-7} \ N-m-rad^{-1}$. Determine the deflection of the galvanometer's pointer if the current through the coil is $1.0 \ mA$. (in $^{\circ}$)

$A$ galvanometer having a coil resistance of $30\,\Omega$ shows full-scale deflection when a current of $2\,A$ passes through it. It can be converted into an ammeter to read currents up to $10\,A$ by:

$A$ moving coil galvanometer has a resistance of $50\,\Omega$ and gives full-scale deflection for $10\,mA$. How could it be converted into an ammeter with a full-scale deflection for $1\,A$?

If only $2 \%$ of the total current passes through an ammeter having a coil of resistance $R$,then the resistance of the shunt of the ammeter is:

$A$ moving coil galvanometer, when shunted with a $2\text{ }\Omega$ resistance, gives a full-scale deflection for a current of $500\text{ mA}$. When a resistance of $470\text{ }\Omega$ is connected in series, it gives a full-scale deflection for a potential of $10\text{ V}$ applied across it. The value of the resistance of the galvanometer coil is . . . . . . $\Omega$.