If the colours of salts of transition element | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The colour of transition metal ions in aqueous solution is primarily due to $d-d$ transitions,which require the presence of unpaired electrons in

Vedclass · Accepted Answer

$Ti^{4+}$

Vedclass · Answer

(B) The colour of transition metal ions in aqueous solution is primarily due to $d-d$ transitions,which require the presence of unpaired electrons in the $d$-orbitals.$1$. Electronic configuration of $Ti$ $(Z=22)$: $[Ar] 3d^2 4s^2$. $Ti^{4+}$ ion: $[Ar] 3d^0 4s^0$. Since there are no unpaired electrons,$Ti^{4+}$ is colourless.$2$. Electronic configuration of $Ti^{3+}$ $(Z=22)$: $[Ar] 3d^1$. It has $1$ unpaired electron,so it is coloured.$3$. Electronic configuration of $Fe^{2+}$ $(Z=26)$: $[Ar] 3d^6$. It has $4$ unpaired electrons,so it is coloured.$4$. Electronic configuration of $Fe^{3+}$ $(Z=26)$: $[Ar] 3d^5$. It has $5$ unpaired electrons,so it is coloured.Therefore,the correct option is $B$.

If the colours of salts of transition elements are due to the presence of unpaired electrons in the transition metal ions,which of the following ions will be colourless in aqueous solution? (The atomic numbers of $Ti$ and $Fe$ are $22$ and $26$ respectively.)

Similar Questions

Which of the following is a coloured compound?

If $A$ is $[Rn]\,6d^2\,7s^2$,then identify the block,period,and group.

Of the following outer electronic configurations of atoms,which one achieves the highest oxidation state?

Which of the following series of transition metal ions has a $3d^2$ electronic configuration?

Which of the following factors may be regarded as the main cause of lanthanide contraction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module