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Question

(C) The compressibility factor $(Z)$ is defined as the ratio of the molar volume of a real gas $(V_m)$ to the molar volume of an ideal gas $(V_{ideal}

Vedclass · Accepted Answer

$23.52$

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(C) The compressibility factor $(Z)$ is defined as the ratio of the molar volume of a real gas $(V_m)$ to the molar volume of an ideal gas $(V_{ideal})$ at the same temperature and pressure.$Z = \frac{V_m}{V_{ideal}}$At $STP$,the molar volume of an ideal gas $(V_{ideal})$ is $22.40 \ dm^3 \ mol^{-1}$.Given $Z = 1.05$,we can calculate the molar volume of the real gas $(V_m)$ as:$V_m = Z 	imes V_{ideal}$$V_m = 1.05 	imes 22.40 \ dm^3 \ mol^{-1}$$V_m = 23.52 \ dm^3 \ mol^{-1}$

If the compressibility factor $(Z)$ of a real gas is $1.05$ at $STP$,what is the molar volume of the real gas (in $dm^3$)?

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