If the density of the earth is doubled keepin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The acceleration due to gravity $g$ is given by the formula $g = \frac{GM}{R^2}$.Substituting the mass of the earth $M = \frac{4}{3} \pi R^3 \rho$

Vedclass · Accepted Answer

$19.6$

Vedclass · Answer

(A) The acceleration due to gravity $g$ is given by the formula $g = \frac{GM}{R^2}$.Substituting the mass of the earth $M = \frac{4}{3} \pi R^3 ho$,where $ho$ is the density,we get:$g = \frac{G}{R^2} 	imes \frac{4}{3} \pi R^3 ho = \frac{4}{3} \pi G R ho$.Since the radius $R$ is kept constant,we have $g \propto ho$.Therefore,the ratio of the new acceleration $g_2$ to the initial acceleration $g_1$ is $\frac{g_2}{g_1} = \frac{ho_2}{ho_1}$.Given that the density is doubled,$ho_2 = 2ho_1$.Thus,$g_2 = 2 	imes g_1 = 2 	imes 9.8\,m/s^2 = 19.6\,m/s^2$.

If the density of the earth is doubled keeping its radius constant,then acceleration due to gravity will be ........ $m/s^2$. $(g = 9.8\,m/s^2)$

Similar Questions

What is the ratio of the rate of diffusion of oxygen $(O_2)$ and hydrogen $(H_2)$?

In which of the genetic disorders does an individual exhibit overall masculine development,gynaecomastia,and sterility?

The radius of an atom is of the order of

Two identical capacitors have the same capacitance $C$. One of them is charged to potential $V_1$ and the other to $V_2$. The negative ends of the capacitors are connected together. When the positive ends are also connected,the decrease in energy of the combined system is

If one of the lines of the pair $ax^2 + 2hxy + by^2 = 0$ bisects the angle between the positive directions of the axes,then $a, b, h$ satisfy the relation:

Vedclass Test Series

Exam Paper Generator

Online Exam Module