If the distance between the points (2, -2) an | vedclass

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(A) The distance formula between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.Given points are $(2,

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$2$

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(A) The distance formula between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.Given points are $(2, -2)$ and $(-1, x)$ with distance $d = 5$.Substituting the values into the formula:$5 = \sqrt{(-1 - 2)^2 + (x - (-2))^2}$$5 = \sqrt{(-3)^2 + (x + 2)^2}$$5 = \sqrt{9 + (x^2 + 4x + 4)}$$5 = \sqrt{x^2 + 4x + 13}$Squaring both sides:$25 = x^2 + 4x + 13$$x^2 + 4x - 12 = 0$Factoring the quadratic equation:$(x + 6)(x - 2) = 0$Thus,$x = -6$ or $x = 2$.Therefore,one of the possible values of $x$ is $2$.

If the distance between the points $(2, -2)$ and $(-1, x)$ is $5$,one of the values of $x$ is

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