If the focal length of the objective lens is | vedclass

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(D) The magnifying power of a compound microscope is given by $m = \left(\frac{L}{f_o}\right) \left(\frac{D}{f_e}\right)$,where $f_o$ is the focal len

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microscope will decrease but that of telescope will increase.

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(D) The magnifying power of a compound microscope is given by $m = \left(\frac{L}{f_o}\right) \left(\frac{D}{f_e}\right)$,where $f_o$ is the focal length of the objective lens,$f_e$ is the focal length of the eyepiece,$L$ is the tube length,and $D$ is the least distance of distinct vision.From this formula,it is clear that $m \propto \frac{1}{f_o}$. Therefore,if $f_o$ increases,the magnifying power of the microscope will decrease.The magnifying power of an astronomical telescope is given by $m = \frac{f_o}{f_e}$,where $f_o$ is the focal length of the objective lens and $f_e$ is the focal length of the eyepiece.From this formula,it is clear that $m \propto f_o$. Therefore,if $f_o$ increases,the magnifying power of the telescope will increase.

If the focal length of the objective lens is increased,then the magnifying power of:

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