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(C) For a quadratic equation of the form $ax^{2} + bx + c = 0$,the roots are equal and real if the discriminant $D = b^{2} - 4ac = 0$.Given the equati

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$9$

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(C) For a quadratic equation of the form $ax^{2} + bx + c = 0$,the roots are equal and real if the discriminant $D = b^{2} - 4ac = 0$.Given the equation $k x^{2} - 24 x + 16 = 0$,we have $a = k$,$b = -24$,and $c = 16$.Substituting these values into the discriminant formula:$(-24)^{2} - 4(k)(16) = 0$$576 - 64k = 0$$64k = 576$$k = \frac{576}{64}$$k = 9$.Therefore,the value of $k$ is $9$.

If the following quadratic equation has two equal and real roots,then find the value of $k$: $k x^{2} - 24 x + 16 = 0$.

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