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(C) For a quadratic equation $ax^2 + bx + c = 0$ to have two equal and real roots,the discriminant $D$ must be equal to $0$.$D = b^2 - 4ac = 0$Here,$a

Vedclass · Accepted Answer

$-2\sqrt{2}$ and $2\sqrt{2}$

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(C) For a quadratic equation $ax^2 + bx + c = 0$ to have two equal and real roots,the discriminant $D$ must be equal to $0$.$D = b^2 - 4ac = 0$Here,$a = 2k$,$b = -8$,and $c = k$.Substituting these values into the discriminant formula:$(-8)^2 - 4(2k)(k) = 0$$64 - 8k^2 = 0$$8k^2 = 64$$k^2 = 8$$k = \pm\sqrt{8}$$k = \pm 2\sqrt{2}$Thus,the values of $k$ are $-2\sqrt{2}$ and $2\sqrt{2}$.

If the following quadratic equation has two equal and real roots,then find the value of $k$: $2kx^2 - 8x + k = 0$.

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