If the following quadratic equation has two equal and real roots,then find the value of $k$: $k x^{2} - 2 \sqrt{5} x + 4 = 0$.

  • A
    $\frac{5}{4}$
  • B
    $\frac{15}{3}$
  • C
    $\frac{4}{1}$
  • D
    $\frac{10}{3}$

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