If the lines $\frac{x-1}{2}=\frac{y+2}{3}=\frac{z-1}{4}$ and $\frac{x-3}{1}=\frac{y-k}{2}=\frac{z}{1}$ intersect,then $k$ has the value

  • A
    $\frac{7}{2}$
  • B
    $\frac{3}{2}$
  • C
    $\frac{-7}{2}$
  • D
    $\frac{-3}{2}$

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If the two lines $\frac{x - 1}{2} = \frac{y - 1}{3} = \frac{z - 1}{4}$ and $\frac{x - 3}{1} = \frac{y - k}{2} = \frac{z}{1}$ intersect at a point,then find the value of $k$.

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