If the mean and variance of a binomial variate $X$ are $\frac{4}{3}$ and $\frac{8}{9}$ respectively,then $P(X=2)=$

  • A
    $\frac{4}{27}$
  • B
    $\frac{16}{81}$
  • C
    $\frac{8}{27}$
  • D
    $\frac{8}{81}$

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