If the normal to the parabola ${y^2} = 12x$ at the point $(3, 6)$ meets the parabola again at the point $(27, -18)$,then the equation of the circle having this normal chord as its diameter is:
- A${x^2} + {y^2} + 30x + 12y - 27 = 0$
- B${x^2} + {y^2} + 30x + 12y + 27 = 0$
- C${x^2} + {y^2} - 30x - 12y - 27 = 0$
- D${x^2} + {y^2} - 30x + 12y - 27 = 0$
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