If the number 583x437 is completely divisible | vedclass

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Question

(D) number is divisible by $9$ if the sum of its digits is divisible by $9$.The given number is $583x437$.The sum of the digits is $5 + 8 + 3 + x + 4

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(D) number is divisible by $9$ if the sum of its digits is divisible by $9$.The given number is $583x437$.The sum of the digits is $5 + 8 + 3 + x + 4 + 3 + 7 = 30 + x$.For the number to be divisible by $9$,$(30 + x)$ must be a multiple of $9$.The multiples of $9$ greater than $30$ are $36, 45, \dots$.Setting $30 + x = 36$,we get $x = 36 - 30 = 6$.Thus,the smallest whole number in place of $x$ is $6$.

If the number $583x437$ is completely divisible by $9$,then the smallest whole number in the place of the blank digit $x$ will be

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