If the pair of straight lines given by $Ax^2+2Hxy+By^2=0$ $(H^2 > AB)$ forms an equilateral triangle with the line $ax+by+c=0$,then $(A+3B)(3A+B)$ is equal to:

  • A
    $H^2$
  • B
    $-H^2$
  • C
    $2H^2$
  • D
    $4H^2$

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