If the perimeter of a triangle is $20$ and two of its vertices are $(-5, 0)$ and $(6, 0)$,then the locus of the third vertex is:

  • A
    $40 x^2 - 81 y^2 - 40 x - 800 = 0$
  • B
    $40 x^2 + 9 y^2 - 25 x + 800 = 0$
  • C
    $40 x^2 - 9 y^2 = 800$
  • D
    $5 x^2 - 3 y^2 + 3 x - 4 y + 25 = 0$

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