(D) The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$, where $R_0$ is a constant and $A$ is the mass number.Given:$R_1 = 1.5 \text{ fe

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(D) The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$, where $R_0$ is a constant and $A$ is the mass number.Given:$R_1 = 1.5 \text{ fermi}$, $A_1 = 125$$A_2 = 64$We need to find $R_2$.Taking the ratio of the radii:$\frac{R_1}{R_2} = \left( \frac{A_1}{A_2} \right)^{1/3}$$\frac{1.5}{R_2} = \left( \frac{125}{64} \right)^{1/3}$$\frac{1.5}{R_2} = \frac{5}{4}$$R_2 = \frac{1.5 \times 4}{5} = 0.3 \times 4 = 1.2 \text{ fermi}$.

Class 12 Physics Nuclei Composition of Nucleus, Size of the Nucleus, Nuclear force

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If the radius of a nucleus with mass number $125$ is $1.5 \text{ fermi}$, then the radius of a nucleus with mass number $64$ is: (in $\text{ fermi}$)

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A
$0.48$
B
$0.96$
C
$1.92$
D
$1.2$

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Composition of Nucleus, Size of the Nucleus, Nuclear force

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If the radius of a nucleus with mass number $125$ is $1.5 \text{ fermi}$, then the radius of a nucleus with mass number $64$ is: (in $\text{ fermi}$)

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