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(D) The current in a semiconductor is given by $I = n e A v_d$,where $n$ is the concentration,$e$ is the charge,$A$ is the cross-sectional area,and $v

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$\frac{5}{4}$

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(D) The current in a semiconductor is given by $I = n e A v_d$,where $n$ is the concentration,$e$ is the charge,$A$ is the cross-sectional area,and $v_d$ is the drift velocity.For electrons and holes,the ratio of currents is given by:$\frac{I_e}{I_h} = \frac{n_e e A v_e}{n_h e A v_h} = \frac{n_e}{n_h} 	imes \frac{v_e}{v_h}$Given $\frac{n_e}{n_h} = \frac{7}{5}$ and $\frac{I_e}{I_h} = \frac{7}{4}$.Substituting these values:$\frac{7}{4} = \frac{7}{5} 	imes \frac{v_e}{v_h}$$\frac{v_e}{v_h} = \frac{7}{4} 	imes \frac{5}{7} = \frac{5}{4}$.

If the ratio of the concentration of electrons to that of holes in a semiconductor is $\frac{7}{5}$ and the ratio of currents is $\frac{7}{4}$,then what is the ratio of their drift velocities?

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