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Question

(C) The maximum amplitude of an amplitude modulated wave is given by $A_{max} = A_c + A_m$ and the minimum amplitude is given by $A_{min} = A_c - A_m$

Vedclass · Accepted Answer

$0.4$

Vedclass · Answer

(C) The maximum amplitude of an amplitude modulated wave is given by $A_{max} = A_c + A_m$ and the minimum amplitude is given by $A_{min} = A_c - A_m$,where $A_c$ is the carrier amplitude and $A_m$ is the message signal amplitude.Given the ratio $\frac{A_{max}}{A_{min}} = \frac{7}{3}$.We know that the modulation index $\mu$ is defined as $\mu = \frac{A_m}{A_c}$.From the ratio,we have $3(A_c + A_m) = 7(A_c - A_m)$.$3A_c + 3A_m = 7A_c - 7A_m$.$10A_m = 4A_c$.$\frac{A_m}{A_c} = \frac{4}{10} = 0.4$.Therefore,the modulation index $\mu = 0.4$.

If the ratio of the maximum and minimum amplitudes of an amplitude modulated wave is $7:3$,then the modulation index is

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