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(B) The slope of the line is $m = \frac{3}{4} = 	an 	heta$. Thus,$\cos 	heta = \frac{4}{5}$ and $\sin 	heta = \frac{3}{5}$.The coordinates of poin

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$(7, 5), (-1, -1)$

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(B) The slope of the line is $m = \frac{3}{4} = 	an 	heta$. Thus,$\cos 	heta = \frac{4}{5}$ and $\sin 	heta = \frac{3}{5}$.The coordinates of points at a distance $r = 5$ from $A(x_1, y_1) = (3, 2)$ are given by $(x_1 \pm r \cos 	heta, y_1 \pm r \sin 	heta)$.For the positive direction: $(3 + 5 	imes \frac{4}{5}, 2 + 5 	imes \frac{3}{5}) = (3 + 4, 2 + 3) = (7, 5)$.For the negative direction: $(3 - 5 	imes \frac{4}{5}, 2 - 5 	imes \frac{3}{5}) = (3 - 4, 2 - 3) = (-1, -1)$.Thus,the required points are $(7, 5)$ and $(-1, -1)$.

If the slope of a line passing through the point $A(3, 2)$ is $3/4$,then the points on the line which are $5$ units away from $A$ are:

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