If the sum of the slopes of the pair of lines | vedclass

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(B) Comparing the given equation $4x^2 + 2hxy - 7y^2 = 0$ with the standard form $ax^2 + 2hxy + by^2 = 0$,we get $a = 4$,$2h = 2h$,and $b = -7$.Let $m

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$-2$

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(B) Comparing the given equation $4x^2 + 2hxy - 7y^2 = 0$ with the standard form $ax^2 + 2hxy + by^2 = 0$,we get $a = 4$,$2h = 2h$,and $b = -7$.Let $m_1$ and $m_2$ be the slopes of the pair of lines.The sum of the slopes is $m_1 + m_2 = -\frac{2h}{b} = -\frac{2h}{-7} = \frac{2h}{7}$.The product of the slopes is $m_1m_2 = \frac{a}{b} = \frac{4}{-7}$.Given that the sum of the slopes is equal to the product of the slopes,we have $m_1 + m_2 = m_1m_2$.Substituting the values,we get $\frac{2h}{7} = \frac{4}{-7}$.Multiplying both sides by $7$,we get $2h = -4$.Therefore,$h = -2$.

If the sum of the slopes of the pair of lines represented by $4x^2 + 2hxy - 7y^2 = 0$ is equal to the product of the slopes,then the value of $h$ is

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