If the vertices of a triangle are A(1, 4),B(3 | vedclass

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(A) The median passing through vertex $C$ connects $C$ to the midpoint of the opposite side $AB$.Let $M$ be the midpoint of $AB$. The coordinates of $

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$1$

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(A) The median passing through vertex $C$ connects $C$ to the midpoint of the opposite side $AB$.Let $M$ be the midpoint of $AB$. The coordinates of $M$ are given by the midpoint formula: $M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) = \left( \frac{1 + 3}{2}, \frac{4 + 0}{2} \right) = (2, 2)$.The length of the median is the distance between $C(2, 1)$ and $M(2, 2)$.Using the distance formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$,we get:$d = \sqrt{(2 - 2)^2 + (2 - 1)^2} = \sqrt{0^2 + 1^2} = \sqrt{1} = 1$.

If the vertices of a triangle are $A(1, 4)$,$B(3, 0)$,and $C(2, 1)$,then the length of the median passing through $C$ is

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