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(B) The coefficient of volume expansion $\gamma$ is defined by the relation $\frac{\Delta V}{V} = \gamma \Delta T$.Given $\frac{\Delta V}{V} = 0.12\%

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$2 	imes 10^{-5}$

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(B) The coefficient of volume expansion $\gamma$ is defined by the relation $\frac{\Delta V}{V} = \gamma \Delta T$.Given $\frac{\Delta V}{V} = 0.12\% = 0.0012$ and $\Delta T = 20^{\circ}C$.Substituting the values,we get $\gamma = \frac{\Delta V}{V \Delta T} = \frac{0.0012}{20} = 6 	imes 10^{-5} /^{\circ}C$.The relationship between the coefficient of linear expansion $\alpha$ and the coefficient of volume expansion $\gamma$ is $\alpha = \frac{\gamma}{3}$.Therefore,$\alpha = \frac{6 	imes 10^{-5}}{3} = 2 	imes 10^{-5} /^{\circ}C$.

If the volume of a block of metal changes by $0.12\%$ when it is heated through $20^{\circ}C$,the coefficient of linear expansion (in per $^{\circ}C^{-1}$) of the metal is :-

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