If two regular six-sided dice are thrown,the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When two six-sided dice are thrown,the total number of possible outcomes is $6^2 = 36$.The possible sums range from $2$ to $12$.The prime numbers

Vedclass · Accepted Answer

$\frac{5}{12}$

Vedclass · Answer

(C) When two six-sided dice are thrown,the total number of possible outcomes is $6^2 = 36$.The possible sums range from $2$ to $12$.The prime numbers between $2$ and $12$ are $\{2, 3, 5, 7, 11\}$.We list the favorable outcomes for each prime sum:- Sum $= 2$: $(1, 1)$ [$1$ outcome]- Sum $= 3$: $(1, 2), (2, 1)$ [$2$ outcomes]- Sum $= 5$: $(1, 4), (4, 1), (2, 3), (3, 2)$ [$4$ outcomes]- Sum $= 7$: $(1, 6), (6, 1), (2, 5), (5, 2), (3, 4), (4, 3)$ [$6$ outcomes]- Sum $= 11$: $(5, 6), (6, 5)$ [$2$ outcomes]Total number of favorable outcomes $= 1 + 2 + 4 + 6 + 2 = 15$.The probability is given by $\frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{15}{36} = \frac{5}{12}$.

If two regular six-sided dice are thrown,the probability that the sum will be a prime number is

Similar Questions

$A$ bag contains $7$ black and $5$ white balls. $A$ ball is drawn out and replaced in the bag. Then a ball is drawn again. What is the probability that the first ball was black and the second white?

From a well-shuffled pack of $52$ cards,one card is drawn at random. The probability that the card drawn is an ace is

$A$ card is drawn at random from a deck of cards. Find the probability of getting the $3$ of diamond.

There are $n$ letters and $n$ addressed envelopes. The probability that each letter is placed in the correct envelope is:

$A$ card is drawn from a pack of $52$ cards. If $A =$ card is of diamond,$B =$ card is an ace and $A \cap B =$ card is the ace of diamond,then events $A$ and $B$ are

Vedclass Test Series

Exam Paper Generator

Online Exam Module