If two wires having resistance R and 2R are j | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The heat generated $H$ is given by the formula $H = \frac{V^2 t}{R}$.Since the voltage $V$ and time $t$ are constant,we have $H \propto \frac{1}{R

Vedclass · Accepted Answer

$2:9$

Vedclass · Answer

(C) The heat generated $H$ is given by the formula $H = \frac{V^2 t}{R}$.Since the voltage $V$ and time $t$ are constant,we have $H \propto \frac{1}{R}$.For series connection,the equivalent resistance is $R_S = R + 2R = 3R$.For parallel connection,the equivalent resistance is $R_P = \frac{R 	imes 2R}{R + 2R} = \frac{2R^2}{3R} = \frac{2}{3}R$.The ratio of heat generated in series to parallel is $\frac{H_S}{H_P} = \frac{R_P}{R_S}$.Substituting the values,we get $\frac{H_S}{H_P} = \frac{(2/3)R}{3R} = \frac{2}{9}$.

If two wires having resistance $R$ and $2R$ are joined in series and then in parallel,what is the ratio of heat generated in these two situations,assuming the same voltage is applied?

Similar Questions

The net current flowing in the given circuit is . . . . . . $\text{A}$.

What is the energy stored in the capacitor of the given circuit?

The charge flowing through a resistance $R$ varies with time as $Q = 2t - 8t^2$. The total heat produced in the resistance is (for $0 \leq t \leq \frac{1}{8} \ s$)

Total $emf$ produced in a thermocouple does not depend on

$A$ cable consists of a copper wire of radius $9 \, mm$ having a resistance of $5 \, \Omega$. If this cable is replaced by $6$ copper wires each of radius $3 \, mm$,what will be the new resistance of the cable in $\Omega$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module