In Delta ABC,mangle B = 90^{circ} and overlin | vedclass

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(C) In a right-angled triangle,the length of the median to the hypotenuse is equal to half the length of the hypotenuse.Given that $\Delta ABC$ is a r

Vedclass · Accepted Answer

$10$

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(C) In a right-angled triangle,the length of the median to the hypotenuse is equal to half the length of the hypotenuse.Given that $\Delta ABC$ is a right-angled triangle with $m\angle B = 90^{\circ}$,the side $\overline{AC}$ is the hypotenuse.$\overline{BM}$ is the median to the hypotenuse $\overline{AC}$.Therefore,$BM = \frac{1}{2} 	imes AC$.Given $AC = 20$,we have $BM = \frac{1}{2} 	imes 20 = 10$.Thus,the correct option is $C$.

In $\Delta ABC$,$m\angle B = 90^{\circ}$ and $\overline{BM}$ is a median. If $AC = 20$,then $BM = \ldots$

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