The length of the hypotenuse of an isosceles | vedclass

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Question

(B) In an isosceles right-angled triangle,the two sides containing the right angle are equal in length.Let the length of each of these sides be $x \,

Vedclass · Accepted Answer

$4 \sqrt{2}$

Vedclass · Answer

(B) In an isosceles right-angled triangle,the two sides containing the right angle are equal in length.Let the length of each of these sides be $x \, cm$.By the Pythagoras theorem,in a right-angled triangle,the square of the hypotenuse is equal to the sum of the squares of the other two sides.Therefore,$(x)^2 + (x)^2 = (8)^2$.$2x^2 = 64$.$x^2 = 32$.$x = \sqrt{32} = \sqrt{16 	imes 2} = 4 \sqrt{2} \, cm$.Since the length cannot be negative,the length of each of the other two sides is $4 \sqrt{2} \, cm$.

The length of the hypotenuse of an isosceles right-angled triangle is $8 \, cm$. Find the length of the other two sides.

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