In triangle ABC,if r=1, R=4 and Delta=8,then | vedclass

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(C) Given,in $	riangle ABC$,$r=1$,$R=4$,and $\Delta=8$.We know that $r = \frac{\Delta}{s}$,where $s$ is the semi-perimeter.$1 = \frac{8}{s} \implies

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$\frac{1}{8}$

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(C) Given,in $	riangle ABC$,$r=1$,$R=4$,and $\Delta=8$.We know that $r = \frac{\Delta}{s}$,where $s$ is the semi-perimeter.$1 = \frac{8}{s} \implies s = 8$.Since $s = \frac{a+b+c}{2}$,we have $a+b+c = 2s = 16$.We also know that $abc = 4R\Delta$.$abc = 4 	imes 4 	imes 8 = 128$.Now,we need to evaluate $\frac{1}{ab} + \frac{1}{bc} + \frac{1}{ca}$.$\frac{1}{ab} + \frac{1}{bc} + \frac{1}{ca} = \frac{c+a+b}{abc} = \frac{a+b+c}{abc}$.Substituting the values,we get $\frac{16}{128} = \frac{1}{8}$.

In $\triangle ABC$,if $r=1, R=4$ and $\Delta=8$,then $\frac{1}{ab}+\frac{1}{bc}+\frac{1}{ca}=$

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