In a capillary tube of radius '$R$',a straight thin metal wire of radius '$r$' is inserted symmetrically and one end of the combination is dipped vertically in water such that the lower end of the capillary and the thin wire are at the same level. If '$T$' is the surface tension of water and '$\rho$' is the density of water, then the rise of water in the capillary is:
- A$T/((R-r)\rho g)$
- B$2T/((R-r)\rho g)$
- C$4T/((R+r)\rho g)$
- D$T/((R+r)\rho g)$
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