In a class of $60$ students, $40$ opted for $NCC$, $30$ opted for $NSS$, and $20$ opted for both $NCC$ and $NSS$. If one of these students is selected at random, then the probability that the selected student has opted for neither $NCC$ nor $NSS$ is

  • A
    $\frac{1}{6}$
  • B
    $\frac{1}{3}$
  • C
    $\frac{2}{3}$
  • D
    $\frac{5}{6}$

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If $X$ and $Y$ are two sets such that $X$ has $40$ elements,$X \cup Y$ has $60$ elements and $X \cap Y$ has $10$ elements,how many elements does $Y$ have?

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