In a diode AM-detector,the output circuit con | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For proper demodulation in a diode $AM$-detector,the condition $\frac{1}{f_c} \ll RC$ must be satisfied,where $f_c$ is the carrier frequency.Given

Vedclass · Accepted Answer

No

Vedclass · Answer

(B) For proper demodulation in a diode $AM$-detector,the condition $\frac{1}{f_c} \ll RC$ must be satisfied,where $f_c$ is the carrier frequency.Given:$f_c = 100 \, kHz = 10^5 \, Hz$$R = 1 \, k\Omega = 10^3 \, \Omega$$C = 10 \, pF = 10 	imes 10^{-12} \, F = 10^{-11} \, F$Calculating $\frac{1}{f_c}$:$\frac{1}{f_c} = \frac{1}{10^5} = 10^{-5} \, s$Calculating $RC$:$RC = 10^3 	imes 10^{-11} = 10^{-8} \, s$Comparing the values:We observe that $10^{-5} \, s > 10^{-8} \, s$,which means $\frac{1}{f_c} > RC$.Since the condition $\frac{1}{f_c} \ll RC$ is not satisfied,the circuit is not good for detection.

In a diode $AM$-detector,the output circuit consists of $R = 1 \, k\Omega$ and $C = 10 \, pF$. $A$ carrier signal of $100 \, kHz$ is to be detected. Is it good?

Similar Questions

Which of the following represents a reverse-biased diode?

Which of the following statements is not correct when a junction diode is in forward bias?

The dominant mechanisms for motion of charge carriers in forward and reverse biased silicon $P-N$ junctions are

The characteristic graph of a diode at different temperatures is shown. What is the relationship between the temperatures?

Assuming that the junction diode is ideal, the current in the arrangement shown in the figure is: (in $\text{mA}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module