In a given series $LCR$ circuit,$R = 4\,\Omega$,$X_L = 5\,\Omega$,and $X_C = 8\,\Omega$. The current:

In the given $AC$ circuit,the phase difference between $I_1$ and $I_2$ is:

In a series $L-C-R$ circuit,the current in the circuit is $11 \, A$ when the applied voltage is $220 \, V$. The voltage across the capacitor is $200 \, V$. If the value of the resistor is $20 \, \Omega$,then the voltage across the unknown inductor is.......$V$

In an $LC$ circuit,the inductance $L = 40 \; mH$ and capacitance $C = 100 \; \mu F$. If a voltage $V(t) = 10 \sin (314 t)$ is applied to the circuit,the current in the circuit is given by:

An e.m.f. $E = 4 \cos(1000t) \, V$ is applied to an $LR$-circuit of inductance $3 \, mH$ and resistance $4 \, \Omega$. The amplitude of current in the circuit is:

When a $DC$ voltage of $100 \, V$ is applied to an inductor, a $DC$ current of $5 \, A$ flows through it. When an $AC$ voltage of $200 \, V$ peak value is connected to the inductor, its inductive reactance is found to be $20\sqrt{3} \, \Omega$. The power dissipated in the circuit is . . . . . . $W$.